According to Google:
Methane, ethane, and propane are non-polar molecules, thus they are not soluble in water. You may have heard like dissolves like , since water is polar, it naturally tends to dissolve with other polar molecules.
Butane is a gas that can slightly adsorb into water, resulting in a low solubility (6.1 mg per 100 g of water).
Carbon dioxide content in air is only 0.03%, but it is highly soluble in water unlike oxygen and one volume of CO2 dissolves in equal volume of water, the solubility being higher at low temperature
I have an idea. After drowning, let's assume, laryngospasm won't occur and lungs will be full of seawater. Let's also assume that these gases solubility don't change for seawater.
This means that after lungs are full of water, toxic butane, propane gases will remain inside lungs. They won't disappear, their effects won't be reduced due to their low solubility in water and seawater.
But on the other hand, CO2 is highly soluble, it means that once my lungs are full of seawater, I won't experience suffocation sensation triggered by high CO2 anymore, since accumulating CO2 in my lungs will be dissolved
If I didn't use gases like butane, I would feel better and relieved that inside sea, I won't experience horrible suffocation due to asphyxiation, because CO2 is soluble in water, especially at lower hypothermia temperatures. Seawater will make CO2 disappear from lungs
I googled, it turns out that oxygen is low soluble in water. Theoretically, when I start drowning, my lungs full of water and oxygen, I can be rescued. Oxygen will remain inside lungs, it won't dissolve in water.
This is all very good, even after drowning, butane and propane will remain inside lungs with their toxic, destructive effects. Suffocation sensation triggering CO2 should disappear from lungs after contact and solubility with water.
Methane, ethane, and propane are non-polar molecules, thus they are not soluble in water. You may have heard like dissolves like , since water is polar, it naturally tends to dissolve with other polar molecules.
Butane is a gas that can slightly adsorb into water, resulting in a low solubility (6.1 mg per 100 g of water).
Carbon dioxide content in air is only 0.03%, but it is highly soluble in water unlike oxygen and one volume of CO2 dissolves in equal volume of water, the solubility being higher at low temperature
I have an idea. After drowning, let's assume, laryngospasm won't occur and lungs will be full of seawater. Let's also assume that these gases solubility don't change for seawater.
This means that after lungs are full of water, toxic butane, propane gases will remain inside lungs. They won't disappear, their effects won't be reduced due to their low solubility in water and seawater.
But on the other hand, CO2 is highly soluble, it means that once my lungs are full of seawater, I won't experience suffocation sensation triggered by high CO2 anymore, since accumulating CO2 in my lungs will be dissolved
If I didn't use gases like butane, I would feel better and relieved that inside sea, I won't experience horrible suffocation due to asphyxiation, because CO2 is soluble in water, especially at lower hypothermia temperatures. Seawater will make CO2 disappear from lungs
I googled, it turns out that oxygen is low soluble in water. Theoretically, when I start drowning, my lungs full of water and oxygen, I can be rescued. Oxygen will remain inside lungs, it won't dissolve in water.
This is all very good, even after drowning, butane and propane will remain inside lungs with their toxic, destructive effects. Suffocation sensation triggering CO2 should disappear from lungs after contact and solubility with water.
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